Search a number
-
+
133102511147 is a prime number
BaseRepresentation
bin111101111110110000…
…1110010010000101011
3110201120010212010211002
41323331201302100223
54140043220324042
6141051344425215
712421255451234
oct1737541622053
9421503763732
10133102511147
11514a2996731
122196791820b
13c72289b848
14662955808b
1536e0406132
hex1efd87242b

133102511147 has 2 divisors, whose sum is σ = 133102511148. Its totient is φ = 133102511146.

The previous prime is 133102511141. The next prime is 133102511153. The reversal of 133102511147 is 741115201331.

It is a balanced prime because it is at equal distance from previous prime (133102511141) and next prime (133102511153).

It is a cyclic number.

It is not a de Polignac number, because 133102511147 - 26 = 133102511083 is a prime.

It is not a weakly prime, because it can be changed into another prime (133102511141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551255573 + 66551255574.

It is an arithmetic number, because the mean of its divisors is an integer number (66551255574).

Almost surely, 2133102511147 is an apocalyptic number.

133102511147 is a deficient number, since it is larger than the sum of its proper divisors (1).

133102511147 is an equidigital number, since it uses as much as digits as its factorization.

133102511147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 29.

Adding to 133102511147 its reverse (741115201331), we get a palindrome (874217712478).

The spelling of 133102511147 in words is "one hundred thirty-three billion, one hundred two million, five hundred eleven thousand, one hundred forty-seven".