133103113333 has 2 divisors, whose sum is σ = 133103113334. Its totient is φ = 133103113332.

The previous prime is 133103113331. The next prime is 133103113337. The reversal of 133103113333 is 333311301331.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 130002071364 + 3101041969 = 360558^2 + 55687^2 .

It is an emirp because it is prime and its reverse (333311301331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133103113333 - 2¹ = 133103113331 is a prime.

Together with 133103113331, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 133103113298 and 133103113307.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133103113331) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66551556666 + 66551556667.

It is an arithmetic number, because the mean of its divisors is an integer number (66551556667).

Almost surely, 2^133103113333 is an apocalyptic number.

It is an amenable number.

133103113333 is a deficient number, since it is larger than the sum of its proper divisors (1).

133103113333 is an equidigital number, since it uses as much as digits as its factorization.

133103113333 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2187, while the sum is 25.

Adding to 133103113333 its reverse (333311301331), we get a palindrome (466414414664).

The spelling of 133103113333 in words is "one hundred thirty-three billion, one hundred three million, one hundred thirteen thousand, three hundred thirty-three".