13310404000421 has 16 divisors (see below), whose sum is σ = 14655051290880. Its totient is φ = 11988212950080.

The previous prime is 13310404000403. The next prime is 13310404000427. The reversal of 13310404000421 is 12400040401331.

It is a cyclic number.

It is not a de Polignac number, because 13310404000421 - 2⁶ = 13310404000357 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13310404000427) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 12194495 + ... + 13241091.

It is an arithmetic number, because the mean of its divisors is an integer number (915940705680).

Almost surely, 2^{13310404000421} is an apocalyptic number.

13310404000421 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13310404000421 is a deficient number, since it is larger than the sum of its proper divisors (1344647290459).

13310404000421 is a wasteful number, since it uses less digits than its factorization.

13310404000421 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1057324.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 13310404000421 its reverse (12400040401331), we get a palindrome (25710444401752).

The spelling of 13310404000421 in words is "thirteen trillion, three hundred ten billion, four hundred four million, four hundred twenty-one", and thus it is an aban number.