Base | Representation |
---|---|
bin | 1100000110110001000111… |
… | …1001110111001111010011 |
3 | 1202010110110221110010002111 |
4 | 3001230101321313033103 |
5 | 3221034201413001233 |
6 | 44150414252130151 |
7 | 2542434135341161 |
oct | 301542171671723 |
9 | 52113427403074 |
10 | 13310404031443 |
11 | 4271a0208a892 |
12 | 15ab78b466957 |
13 | 7572200c7a3c |
14 | 340326c20231 |
15 | 18137a411acd |
hex | c1b11e773d3 |
13310404031443 has 4 divisors (see below), whose sum is σ = 13619948311288. Its totient is φ = 13000859751600.
The previous prime is 13310404031417. The next prime is 13310404031467. The reversal of 13310404031443 is 34413040401331.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13310404031443 - 237 = 13172965077971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13310404331443) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 154772139858 + ... + 154772139943.
It is an arithmetic number, because the mean of its divisors is an integer number (3404987077822).
Almost surely, 213310404031443 is an apocalyptic number.
13310404031443 is a deficient number, since it is larger than the sum of its proper divisors (309544279845).
13310404031443 is an equidigital number, since it uses as much as digits as its factorization.
13310404031443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 309544279844.
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 13310404031443 its reverse (34413040401331), we get a palindrome (47723444432774).
The spelling of 13310404031443 in words is "thirteen trillion, three hundred ten billion, four hundred four million, thirty-one thousand, four hundred forty-three".
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