13311001130000 has 400 divisors, whose sum is σ = 37666669607424. Its totient is φ = 4460513280000.

The previous prime is 13311001129991. The next prime is 13311001130039. The reversal of 13311001130000 is 3110011331.

It is a happy number.

It is a tau number, because it is divible by the number of its divisors (400).

It is a super-2 number, since 2×13311001130000² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (14).

It is an unprimeable number.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 2819527640 + ... + 2819532360.

Almost surely, 2^{13311001130000} is an apocalyptic number.

13311001130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311001130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18833334803712).

13311001130000 is an abundant number, since it is smaller than the sum of its proper divisors (24355668477424).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311001130000 is an equidigital number, since it uses as much as digits as its factorization.

13311001130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5660 (or 5639 counting only the distinct ones).

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 13311001130000 its reverse (3110011331), we get a palindrome (13314111141331).

The spelling of 13311001130000 in words is "thirteen trillion, three hundred eleven billion, one million, one hundred thirty thousand".