133110030121333 has 4 divisors (see below), whose sum is σ = 138897422735328. Its totient is φ = 127322637507340.

The previous prime is 133110030121283. The next prime is 133110030121339. The reversal of 133110030121333 is 333121030011331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133110030121333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133110030121298 and 133110030121307.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133110030121339) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2893696306963 + ... + 2893696307008.

It is an arithmetic number, because the mean of its divisors is an integer number (34724355683832).

Almost surely, 2^{133110030121333} is an apocalyptic number.

It is an amenable number.

133110030121333 is a deficient number, since it is larger than the sum of its proper divisors (5787392613995).

133110030121333 is an equidigital number, since it uses as much as digits as its factorization.

133110030121333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5787392613994.

The product of its (nonzero) digits is 1458, while the sum is 25.

Adding to 133110030121333 its reverse (333121030011331), we get a palindrome (466231060132664).

The spelling of 133110030121333 in words is "one hundred thirty-three trillion, one hundred ten billion, thirty million, one hundred twenty-one thousand, three hundred thirty-three".