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133111010103012 = 22323697528058417
BaseRepresentation
bin11110010001000001010010…
…011110010000111011100100
3122110022021210011101002102200
4132101001102132100323210
5114421342322041244022
61151034204233134500
740015644630236004
oct3621012236207344
9573267704332380
10133111010103012
1139460076008397
1212b1997bb5a430
135937411948876
1424c2870496004
15105c7c990ebac
hex791052790ee4

133111010103012 has 18 divisors (see below), whose sum is σ = 336475053316038. Its totient is φ = 44370336700992.

The previous prime is 133111010103011. The next prime is 133111010103017. The reversal of 133111010103012 is 210301010111331.

133111010103012 is a `hidden beast` number, since 1 + 331 + 1 + 10 + 10 + 10 + 301 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 93105208002816 + 40005802100196 = 9649104^2 + 6325014^2 .

It is a tau number, because it is divible by the number of its divisors (18).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (133111010103011) by changing a digit.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 1848764029173 + ... + 1848764029244.

Almost surely, 2133111010103012 is an apocalyptic number.

133111010103012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

133111010103012 is an abundant number, since it is smaller than the sum of its proper divisors (203364043213026).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133111010103012 is a wasteful number, since it uses less digits than its factorization.

133111010103012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3697528058427 (or 3697528058422 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 133111010103012 its reverse (210301010111331), we get a palindrome (343412020214343).

The spelling of 133111010103012 in words is "one hundred thirty-three trillion, one hundred eleven billion, ten million, one hundred three thousand, twelve".

Divisors: 1 2 3 4 6 9 12 18 36 3697528058417 7395056116834 11092584175251 14790112233668 22185168350502 33277752525753 44370336701004 66555505051506 133111010103012