Base | Representation |
---|---|
bin | 1100000110110011110010… |
… | …0101100100101110001000 |
3 | 1202010112022211220211202101 |
4 | 3001230330211210232020 |
5 | 3221042133223224000 |
6 | 44151013312443144 |
7 | 2542460652163624 |
oct | 301547445445610 |
9 | 52115284824671 |
10 | 13311120133000 |
11 | 427223a327558 |
12 | 15ab94b2494b4 |
13 | 757305583c81 |
14 | 340393d8a184 |
15 | 1813bd214e6a |
hex | c1b3c964b88 |
13311120133000 has 64 divisors (see below), whose sum is σ = 31149549475200. Its totient is φ = 5324186795200.
The previous prime is 13311120132953. The next prime is 13311120133063. The reversal of 13311120133000 is 33102111331.
It is a super-3 number, since 3×133111201330003 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 20742957 + ... + 21375043.
It is an arithmetic number, because the mean of its divisors is an integer number (486711710550).
Almost surely, 213311120133000 is an apocalyptic number.
13311120133000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13311120133000 is an abundant number, since it is smaller than the sum of its proper divisors (17838429342200).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13311120133000 is a wasteful number, since it uses less digits than its factorization.
13311120133000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 653167 (or 653153 counting only the distinct ones).
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 13311120133000 its reverse (33102111331), we get a palindrome (13344222244331).
The spelling of 13311120133000 in words is "thirteen trillion, three hundred eleven billion, one hundred twenty million, one hundred thirty-three thousand".
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