13311200023001 has 4 divisors (see below), whose sum is σ = 13889947850112. Its totient is φ = 12732452195892.

The previous prime is 13311200022977. The next prime is 13311200023007. The reversal of 13311200023001 is 10032000211331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13311200023001 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13311200023007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289373913521 + ... + 289373913566.

It is an arithmetic number, because the mean of its divisors is an integer number (3472486962528).

Almost surely, 2^{13311200023001} is an apocalyptic number.

It is an amenable number.

13311200023001 is a deficient number, since it is larger than the sum of its proper divisors (578747827111).

13311200023001 is an equidigital number, since it uses as much as digits as its factorization.

13311200023001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 578747827110.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13311200023001 its reverse (10032000211331), we get a palindrome (23343200234332).

The spelling of 13311200023001 in words is "thirteen trillion, three hundred eleven billion, two hundred million, twenty-three thousand, one".