13311210023 has 4 divisors (see below), whose sum is σ = 13312167720. Its totient is φ = 13310252328.

The previous prime is 13311210013. The next prime is 13311210041. The reversal of 13311210023 is 32001211331.

13311210023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13311210023 - 2⁴ = 13311210007 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13311209983 and 13311210010.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311210013) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 457688 + ... + 485901.

It is an arithmetic number, because the mean of its divisors is an integer number (3328041930).

Almost surely, 2^13311210023 is an apocalyptic number.

13311210023 is a deficient number, since it is larger than the sum of its proper divisors (957697).

13311210023 is an equidigital number, since it uses as much as digits as its factorization.

13311210023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 957696.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13311210023 its reverse (32001211331), we get a palindrome (45312421354).

The spelling of 13311210023 in words is "thirteen billion, three hundred eleven million, two hundred ten thousand, twenty-three".