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13311210414400 = 2652173313153641
BaseRepresentation
bin1100000110110100000111…
…1101111110000101000000
31202010112120010210121112221
43001231001331332011000
53221042324331230100
644151030255500424
72542463126440663
oct301550175760500
952115503717487
1013311210414400
114272286290288
1215ab975527714
1375731b1a4012
143403a1d6b6da
151813c60ea01a
hexc1b41f7e140

13311210414400 has 168 divisors, whose sum is σ = 33048691036344. Its totient is φ = 5276759654400.

The previous prime is 13311210414391. The next prime is 13311210414407. The reversal of 13311210414400 is 441401211331.

It can be written as a sum of positive squares in 12 ways, for example, as 3201150758976 + 10110059655424 = 1789176^2 + 3179632^2 .

It is a Harshad number since it is a multiple of its sum of digits (25).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311210414407) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 86561580 + ... + 86715220.

Almost surely, 213311210414400 is an apocalyptic number.

13311210414400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311210414400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16524345518172).

13311210414400 is an abundant number, since it is smaller than the sum of its proper divisors (19737480621944).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311210414400 is a wasteful number, since it uses less digits than its factorization.

13311210414400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154149 (or 154134 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13311210414400 its reverse (441401211331), we get a palindrome (13752611625731).

The spelling of 13311210414400 in words is "thirteen trillion, three hundred eleven billion, two hundred ten million, four hundred fourteen thousand, four hundred".