13311213100 has 54 divisors (see below), whose sum is σ = 29513479940. Its totient is φ = 5211111840.

The previous prime is 13311213031. The next prime is 13311213169. The reversal of 13311213100 is 131211331.

It is an interprime number because it is at equal distance from previous prime (13311213031) and next prime (13311213169).

It is a super-2 number, since 2×13311213100² (a number of 21 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 190771 + ... + 251029.

Almost surely, 2^13311213100 is an apocalyptic number.

13311213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311213100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14756739970).

13311213100 is an abundant number, since it is smaller than the sum of its proper divisors (16202266840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311213100 is a wasteful number, since it uses less digits than its factorization.

13311213100 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60367 (or 60313 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13311213100 its reverse (131211331), we get a palindrome (13442424431).

The spelling of 13311213100 in words is "thirteen billion, three hundred eleven million, two hundred thirteen thousand, one hundred".