Search a number
-
+
133112233011133 is a prime number
BaseRepresentation
bin11110010001000010011011…
…010111010010011110111101
3122110022101221101111021000001
4132101002123113102132331
5114421402323122324013
61151034525440234301
740016020136624545
oct3621023327223675
9573271841437001
10133112233011133
1139460643340362
1212b1a06160b991
13593757810103c
1424c2948a6a325
15105c84be72ddd
hex79109b5d27bd

133112233011133 has 2 divisors, whose sum is σ = 133112233011134. Its totient is φ = 133112233011132.

The previous prime is 133112233011083. The next prime is 133112233011137. The reversal of 133112233011133 is 331110332211331.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 76154978729124 + 56957254282009 = 8726682^2 + 7547003^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133112233011133 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133112233011137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556116505566 + 66556116505567.

It is an arithmetic number, because the mean of its divisors is an integer number (66556116505567).

Almost surely, 2133112233011133 is an apocalyptic number.

It is an amenable number.

133112233011133 is a deficient number, since it is larger than the sum of its proper divisors (1).

133112233011133 is an equidigital number, since it uses as much as digits as its factorization.

133112233011133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2916, while the sum is 28.

Adding to 133112233011133 its reverse (331110332211331), we get a palindrome (464222565222464).

The spelling of 133112233011133 in words is "one hundred thirty-three trillion, one hundred twelve billion, two hundred thirty-three million, eleven thousand, one hundred thirty-three".