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133112301123103 = 421409315874367
BaseRepresentation
bin11110010001000010011111…
…011011000111011000011111
3122110022102010010122201001121
4132101002133123013120133
5114421402443041414403
61151034540312151411
740016021624565661
oct3621023733073037
9573272103581047
10133112301123103
1139460678831945
1212b1a080398567
13593758925b393
1424c2953b1a531
15105c852e293bd
hex79109f6c761f

133112301123103 has 4 divisors (see below), whose sum is σ = 133112617418880. Its totient is φ = 133111984827328.

The previous prime is 133112301123091. The next prime is 133112301123107. The reversal of 133112301123103 is 301321103211331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133112301123103 - 225 = 133112267568671 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133112301123107) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 157515775 + ... + 158358592.

It is an arithmetic number, because the mean of its divisors is an integer number (33278154354720).

Almost surely, 2133112301123103 is an apocalyptic number.

133112301123103 is a deficient number, since it is larger than the sum of its proper divisors (316295777).

133112301123103 is an equidigital number, since it uses as much as digits as its factorization.

133112301123103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 316295776.

The product of its (nonzero) digits is 972, while the sum is 25.

Adding to 133112301123103 its reverse (301321103211331), we get a palindrome (434433404334434).

The spelling of 133112301123103 in words is "one hundred thirty-three trillion, one hundred twelve billion, three hundred one million, one hundred twenty-three thousand, one hundred three".

Divisors: 1 421409 315874367 133112301123103