Base | Representation |
---|---|
bin | 1100000110110100001101… |
… | …0000101110110111000111 |
3 | 1202010112121122121212100112 |
4 | 3001231003100232313013 |
5 | 3221042400410010043 |
6 | 44151032352503235 |
7 | 2542463512031351 |
oct | 301550320566707 |
9 | 52115548555315 |
10 | 13311232110023 |
11 | 4272297559551 |
12 | 15ab98084ab1b |
13 | 75732282c173 |
14 | 3403a4bb80d1 |
15 | 1813c7e83518 |
hex | c1b4342edc7 |
13311232110023 has 2 divisors, whose sum is σ = 13311232110024. Its totient is φ = 13311232110022.
The previous prime is 13311232109971. The next prime is 13311232110041. The reversal of 13311232110023 is 32001123211331.
13311232110023 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13311232110023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13311232110223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655616055011 + 6655616055012.
It is an arithmetic number, because the mean of its divisors is an integer number (6655616055012).
Almost surely, 213311232110023 is an apocalyptic number.
13311232110023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13311232110023 is an equidigital number, since it uses as much as digits as its factorization.
13311232110023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 13311232110023 its reverse (32001123211331), we get a palindrome (45312355321354).
The spelling of 13311232110023 in words is "thirteen trillion, three hundred eleven billion, two hundred thirty-two million, one hundred ten thousand, twenty-three".
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