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13311301222103 = 62572127425479
BaseRepresentation
bin1100000110110100011101…
…1000010111111011010111
31202010112210110200010022012
43001231013120113323113
53221043021103101403
644151043302054435
72542465311336323
oct301550730277327
952115713603265
1013311301222103
114272322573475
1215ab99ba1a41b
13757333c497a1
143403b0048983
151813ce085ed8
hexc1b47617ed7

13311301222103 has 4 divisors (see below), whose sum is σ = 13313428653840. Its totient is φ = 13309173790368.

The previous prime is 13311301222049. The next prime is 13311301222123. The reversal of 13311301222103 is 30122210311331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13311301222103 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311301222123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1063706483 + ... + 1063718996.

It is an arithmetic number, because the mean of its divisors is an integer number (3328357163460).

Almost surely, 213311301222103 is an apocalyptic number.

13311301222103 is a deficient number, since it is larger than the sum of its proper divisors (2127431737).

13311301222103 is an equidigital number, since it uses as much as digits as its factorization.

13311301222103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2127431736.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13311301222103 its reverse (30122210311331), we get a palindrome (43433511533434).

The spelling of 13311301222103 in words is "thirteen trillion, three hundred eleven billion, three hundred one million, two hundred twenty-two thousand, one hundred three".

Divisors: 1 6257 2127425479 13311301222103