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13311310102 = 26655655051
BaseRepresentation
bin11000110010110101…
…00111100100010110
31021100200120121122021
430121122213210112
5204230143410402
610040511323354
7650603161156
oct143132474426
937320517567
1013311310102
115710984332
1226b5b2055a
131341a2c76c
14903c44766
1552d946d37
hex3196a7916

13311310102 has 4 divisors (see below), whose sum is σ = 19966965156. Its totient is φ = 6655655050.

The previous prime is 13311310081. The next prime is 13311310121. The reversal of 13311310102 is 20101311331.

13311310102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3327827524 + ... + 3327827527.

It is an arithmetic number, because the mean of its divisors is an integer number (4991741289).

Almost surely, 213311310102 is an apocalyptic number.

13311310102 is a deficient number, since it is larger than the sum of its proper divisors (6655655054).

13311310102 is an equidigital number, since it uses as much as digits as its factorization.

13311310102 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6655655053.

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13311310102 its reverse (20101311331), we get a palindrome (33412621433).

The spelling of 13311310102 in words is "thirteen billion, three hundred eleven million, three hundred ten thousand, one hundred two".

Divisors: 1 2 6655655051 13311310102