Base | Representation |
---|---|
bin | 111101111111000101… |
… | …0001110001000111101 |
3 | 110201120212210200012222 |
4 | 1323332022032020331 |
5 | 4140103424023401 |
6 | 141052403535125 |
7 | 12421444530005 |
oct | 1737612161075 |
9 | 421525720188 |
10 | 133113111101 |
11 | 514a8976623 |
12 | 2196b38a4a5 |
13 | c724b404c9 |
14 | 662ab17005 |
15 | 36e12ebc1b |
hex | 1efe28e23d |
133113111101 has 2 divisors, whose sum is σ = 133113111102. Its totient is φ = 133113111100.
The previous prime is 133113111097. The next prime is 133113111143. The reversal of 133113111101 is 101111311331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 115753731076 + 17359380025 = 340226^2 + 131755^2 .
It is a cyclic number.
It is not a de Polignac number, because 133113111101 - 22 = 133113111097 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is a self number, because there is not a number n which added to its sum of digits gives 133113111101.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133113111181) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556555550 + 66556555551.
It is an arithmetic number, because the mean of its divisors is an integer number (66556555551).
Almost surely, 2133113111101 is an apocalyptic number.
It is an amenable number.
133113111101 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113111101 is an equidigital number, since it uses as much as digits as its factorization.
133113111101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 27, while the sum is 17.
Adding to 133113111101 its reverse (101111311331), we get a palindrome (234224422432).
The spelling of 133113111101 in words is "one hundred thirty-three billion, one hundred thirteen million, one hundred eleven thousand, one hundred one".
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