Base | Representation |
---|---|
bin | 1100000110110100011111… |
… | …1110011011111011111111 |
3 | 1202010112211011110001101220 |
4 | 3001231013332123323333 |
5 | 3221043031131344444 |
6 | 44151044300004423 |
7 | 2542465462214361 |
oct | 301550776337377 |
9 | 52115734401356 |
10 | 13311311199999 |
11 | 4272328168a6a |
12 | 15ab9a3230713 |
13 | 757336031277 |
14 | 3403b14c4d31 |
15 | 1813ceda7619 |
hex | c1b47f9beff |
13311311199999 has 4 divisors (see below), whose sum is σ = 17748414933336. Its totient is φ = 8874207466664.
The previous prime is 13311311199983. The next prime is 13311311200013. The reversal of 13311311199999 is 99999111311331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13311311199999 - 24 = 13311311199983 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13311311199299) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218551866664 + ... + 2218551866669.
It is an arithmetic number, because the mean of its divisors is an integer number (4437103733334).
Almost surely, 213311311199999 is an apocalyptic number.
13311311199999 is a deficient number, since it is larger than the sum of its proper divisors (4437103733337).
13311311199999 is an equidigital number, since it uses as much as digits as its factorization.
13311311199999 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4437103733336.
The product of its digits is 1594323, while the sum is 60.
The spelling of 13311311199999 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, one hundred ninety-nine thousand, nine hundred ninety-nine".
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