13311311200000 has 432 divisors, whose sum is σ = 36289919296512. Its totient is φ = 4832524800000.

The previous prime is 13311311199983. The next prime is 13311311200013. The reversal of 13311311200000 is 211311331.

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 9354399289 + ... + 9354400711.

It is an arithmetic number, because the mean of its divisors is an integer number (84004442816).

Almost surely, 2^{13311311200000} is an apocalyptic number.

13311311200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13311311200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18144959648256).

13311311200000 is an abundant number, since it is smaller than the sum of its proper divisors (22978608096512).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13311311200000 is an equidigital number, since it uses as much as digits as its factorization.

13311311200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2538 (or 2504 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 16.

Adding to 13311311200000 its reverse (211311331), we get a palindrome (13311522511331).

The spelling of 13311311200000 in words is "thirteen trillion, three hundred eleven billion, three hundred eleven million, two hundred thousand".