Base | Representation |
---|---|
bin | 11110010001000011010101… |
… | …000011111000001100000111 |
3 | 122110022111102211221020202212 |
4 | 132101003111003320030013 |
5 | 114421411313424014343 |
6 | 1151035205455454035 |
7 | 40016053132456232 |
oct | 3621032503701407 |
9 | 573274384836685 |
10 | 133113201001223 |
11 | 39460a9a790673 |
12 | 12b1a29182731b |
13 | 59376a0811441 |
14 | 24c29db444419 |
15 | 105c8a6e2ec18 |
hex | 7910d50f8307 |
133113201001223 has 2 divisors, whose sum is σ = 133113201001224. Its totient is φ = 133113201001222.
The previous prime is 133113201001211. The next prime is 133113201001321. The reversal of 133113201001223 is 322100102311331.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 133113201001223 - 214 = 133113200984839 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133113201000223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66556600500611 + 66556600500612.
It is an arithmetic number, because the mean of its divisors is an integer number (66556600500612).
Almost surely, 2133113201001223 is an apocalyptic number.
133113201001223 is a deficient number, since it is larger than the sum of its proper divisors (1).
133113201001223 is an equidigital number, since it uses as much as digits as its factorization.
133113201001223 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 133113201001223 its reverse (322100102311331), we get a palindrome (455213303312554).
The spelling of 133113201001223 in words is "one hundred thirty-three trillion, one hundred thirteen billion, two hundred one million, one thousand, two hundred twenty-three".
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