133113254035 has 8 divisors (see below), whose sum is σ = 161660434320. Its totient is φ = 105207583584.

The previous prime is 133113254033. The next prime is 133113254059. The reversal of 133113254035 is 530452311331.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 133113254035 - 2¹ = 133113254033 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133113253988 and 133113254006.

It is not an unprimeable number, because it can be changed into a prime (133113254033) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 160377000 + ... + 160377829.

It is an arithmetic number, because the mean of its divisors is an integer number (20207554290).

Almost surely, 2^133113254035 is an apocalyptic number.

133113254035 is a deficient number, since it is larger than the sum of its proper divisors (28547180285).

133113254035 is an equidigital number, since it uses as much as digits as its factorization.

133113254035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 320754917.

The product of its (nonzero) digits is 16200, while the sum is 31.

Adding to 133113254035 its reverse (530452311331), we get a palindrome (663565565366).

The spelling of 133113254035 in words is "one hundred thirty-three billion, one hundred thirteen million, two hundred fifty-four thousand, thirty-five".