Base | Representation |
---|---|
bin | 11110010001000011011010… |
… | …111110110000011101000011 |
3 | 122110022111200202211021102102 |
4 | 132101003122332300131003 |
5 | 114421412014340301430 |
6 | 1151035223404341015 |
7 | 40016055446622431 |
oct | 3621033276603503 |
9 | 573274622737372 |
10 | 133113300322115 |
11 | 39461040858953 |
12 | 12b1a2bab4476b |
13 | 59376b8277ab9 |
14 | 24c2a0a6d9d51 |
15 | 105c8b09ed345 |
hex | 7910dafb0743 |
133113300322115 has 64 divisors (see below), whose sum is σ = 174910663509120. Its totient is φ = 96849515151360.
The previous prime is 133113300322097. The next prime is 133113300322133. The reversal of 133113300322115 is 511223003311331.
It is an interprime number because it is at equal distance from previous prime (133113300322097) and next prime (133113300322133).
It is a de Polignac number, because none of the positive numbers 2k-133113300322115 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1064699087 + ... + 1064824103.
It is an arithmetic number, because the mean of its divisors is an integer number (2732979117330).
Almost surely, 2133113300322115 is an apocalyptic number.
133113300322115 is a deficient number, since it is larger than the sum of its proper divisors (41797363187005).
133113300322115 is a wasteful number, since it uses less digits than its factorization.
133113300322115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 127992.
The product of its (nonzero) digits is 4860, while the sum is 29.
Adding to 133113300322115 its reverse (511223003311331), we get a palindrome (644336303633446).
The spelling of 133113300322115 in words is "one hundred thirty-three trillion, one hundred thirteen billion, three hundred million, three hundred twenty-two thousand, one hundred fifteen".
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