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13311341 = 19996659
BaseRepresentation
bin110010110001…
…110101101101
3221001021201122
4302301311231
511401430331
61153150325
7221100401
oct62616555
927037648
1013311341
11757200a
12455b3a5
1329b0b44
141aa7101
15127e17b
hexcb1d6d

13311341 has 4 divisors (see below), whose sum is σ = 13320000. Its totient is φ = 13302684.

The previous prime is 13311317. The next prime is 13311349. The reversal of 13311341 is 14311331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 13311341 - 222 = 9117037 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13311349) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1331 + ... + 5328.

It is an arithmetic number, because the mean of its divisors is an integer number (3330000).

Almost surely, 213311341 is an apocalyptic number.

It is an amenable number.

13311341 is a deficient number, since it is larger than the sum of its proper divisors (8659).

13311341 is an equidigital number, since it uses as much as digits as its factorization.

13311341 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8658.

The product of its digits is 108, while the sum is 17.

The square root of 13311341 is about 3648.4710496316. The cubic root of 13311341 is about 236.9957745809.

Adding to 13311341 its reverse (14311331), we get a palindrome (27622672).

It can be divided in two parts, 1331 and 1341, that multiplied together give a palindrome (1784871).

The spelling of 13311341 in words is "thirteen million, three hundred eleven thousand, three hundred forty-one".

Divisors: 1 1999 6659 13311341