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1331140002035 = 5536793373943
BaseRepresentation
bin10011010111101110001…
…000001000000011110011
311201020220102202110101212
4103113232020020003303
5133302133320031120
62455303421550335
7165112614220334
oct23275610100363
94636812673355
101331140002035
11473595912668
12195b981153ab
13986ab70794c
14485db18628b
152495cb876c5
hex135ee2080f3

1331140002035 has 16 divisors (see below), whose sum is σ = 1627552989504. Its totient is φ = 1044789812352.

The previous prime is 1331140002013. The next prime is 1331140002047. The reversal of 1331140002035 is 5302000411331.

It is a cyclic number.

It is not a de Polignac number, because 1331140002035 - 212 = 1331139997939 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1331140002035.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 17965274 + ... + 18039216.

It is an arithmetic number, because the mean of its divisors is an integer number (101722061844).

Almost surely, 21331140002035 is an apocalyptic number.

1331140002035 is a deficient number, since it is larger than the sum of its proper divisors (296412987469).

1331140002035 is an equidigital number, since it uses as much as digits as its factorization.

1331140002035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 141934.

The product of its (nonzero) digits is 1080, while the sum is 23.

Adding to 1331140002035 its reverse (5302000411331), we get a palindrome (6633140413366).

The spelling of 1331140002035 in words is "one trillion, three hundred thirty-one billion, one hundred forty million, two thousand, thirty-five".

Divisors: 1 5 53 265 67933 73943 339665 369715 3600449 3918979 18002245 19594895 5023169819 25115849095 266228000407 1331140002035