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1331146568441 is a prime number
BaseRepresentation
bin10011010111101110100…
…001001011001011111001
311201020220220010001211002
4103113232201023023321
5133302142010142231
62455304214414345
7165113024066354
oct23275641131371
94636826101732
101331146568441
11473599598048
12195b9a3613b5
13986acb966b1
14485dbdb529b
152495d5330cb
hex135ee84b2f9

1331146568441 has 2 divisors, whose sum is σ = 1331146568442. Its totient is φ = 1331146568440.

The previous prime is 1331146568431. The next prime is 1331146568443. The reversal of 1331146568441 is 1448656411331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1046588334841 + 284558233600 = 1023029^2 + 533440^2 .

It is a cyclic number.

It is not a de Polignac number, because 1331146568441 - 230 = 1330072826617 is a prime.

Together with 1331146568443, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1331146568443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665573284220 + 665573284221.

It is an arithmetic number, because the mean of its divisors is an integer number (665573284221).

Almost surely, 21331146568441 is an apocalyptic number.

It is an amenable number.

1331146568441 is a deficient number, since it is larger than the sum of its proper divisors (1).

1331146568441 is an equidigital number, since it uses as much as digits as its factorization.

1331146568441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 829440, while the sum is 47.

The spelling of 1331146568441 in words is "one trillion, three hundred thirty-one billion, one hundred forty-six million, five hundred sixty-eight thousand, four hundred forty-one".