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133116474749 is a prime number
BaseRepresentation
bin111101111111001011…
…1000011010101111101
3110201121010010120021112
41323332113003111331
54140110304142444
6141053004011405
712421515236366
oct1737627032575
9421533116245
10133116474749
11514aa8637a5
1221970530b65
13c72574a52b
14662b350b6d
1536e176369e
hex1efe5c357d

133116474749 has 2 divisors, whose sum is σ = 133116474750. Its totient is φ = 133116474748.

The previous prime is 133116474697. The next prime is 133116474763. The reversal of 133116474749 is 947474611331.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 115171996900 + 17944477849 = 339370^2 + 133957^2 .

It is a cyclic number.

It is not a de Polignac number, because 133116474749 - 236 = 64396998013 is a prime.

It is a super-2 number, since 2×1331164747492 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 133116474697 and 133116474706.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133116474949) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66558237374 + 66558237375.

It is an arithmetic number, because the mean of its divisors is an integer number (66558237375).

Almost surely, 2133116474749 is an apocalyptic number.

It is an amenable number.

133116474749 is a deficient number, since it is larger than the sum of its proper divisors (1).

133116474749 is an equidigital number, since it uses as much as digits as its factorization.

133116474749 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1524096, while the sum is 50.

The spelling of 133116474749 in words is "one hundred thirty-three billion, one hundred sixteen million, four hundred seventy-four thousand, seven hundred forty-nine".