Search a number
-
+
133116474949 is a prime number
BaseRepresentation
bin111101111111001011…
…1000011011001000101
3110201121010010120112221
41323332113003121011
54140110304144244
6141053004012341
712421515240103
oct1737627033105
9421533116487
10133116474949
11514aa863967
12219705310b1
13c72574a653
14662b350c73
1536e1763784
hex1efe5c3645

133116474949 has 2 divisors, whose sum is σ = 133116474950. Its totient is φ = 133116474948.

The previous prime is 133116474937. The next prime is 133116474961. The reversal of 133116474949 is 949474611331.

It is a balanced prime because it is at equal distance from previous prime (133116474937) and next prime (133116474961).

It can be written as a sum of positive squares in only one way, i.e., 130622970724 + 2493504225 = 361418^2 + 49935^2 .

It is a cyclic number.

It is not a de Polignac number, because 133116474949 - 29 = 133116474437 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 133116474896 and 133116474905.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133116474749) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66558237474 + 66558237475.

It is an arithmetic number, because the mean of its divisors is an integer number (66558237475).

Almost surely, 2133116474949 is an apocalyptic number.

It is an amenable number.

133116474949 is a deficient number, since it is larger than the sum of its proper divisors (1).

133116474949 is an equidigital number, since it uses as much as digits as its factorization.

133116474949 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1959552, while the sum is 52.

The spelling of 133116474949 in words is "one hundred thirty-three billion, one hundred sixteen million, four hundred seventy-four thousand, nine hundred forty-nine".