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1331200000 = 2155513
BaseRepresentation
bin100111101011000…
…1000000000000000
310102202212222002201
41033112020000000
510211241400000
6340032122544
744663004364
oct11726100000
93382788081
101331200000
11623478299
12311996454
13182a40210
14c8b232a4
157bd0496a
hex4f588000

1331200000 has 192 divisors, whose sum is σ = 3583715940. Its totient is φ = 491520000.

The previous prime is 1331199997. The next prime is 1331200001. The reversal of 1331200000 is 21331.

It can be written as a sum of positive squares in 6 ways, for example, as 363741184 + 967458816 = 19072^2 + 31104^2 .

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 1331200000.

It is not an unprimeable number, because it can be changed into a prime (1331200001) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 102399994 + ... + 102400006.

Almost surely, 21331200000 is an apocalyptic number.

1331200000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331200000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1791857970).

1331200000 is an abundant number, since it is smaller than the sum of its proper divisors (2252515940).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331200000 is an frugal number, since it uses more digits than its factorization.

1331200000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 68 (or 20 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

The square root of 1331200000 is about 36485.6136031724. The cubic root of 1331200000 is about 1100.0550936593.

Adding to 1331200000 its reverse (21331), we get a palindrome (1331221331).

The spelling of 1331200000 in words is "one billion, three hundred thirty-one million, two hundred thousand".