Base | Representation |
---|---|
bin | 11110010001001001110001… |
… | …000011011100100111111110 |
3 | 122110100011021120021022112210 |
4 | 132101021301003130213332 |
5 | 114422014442423220220 |
6 | 1151042311414041250 |
7 | 40016416333400436 |
oct | 3621116103344776 |
9 | 573304246238483 |
10 | 133120113101310 |
11 | 39463a17458785 |
12 | 12b1b6a0649226 |
13 | 593823284c2aa |
14 | 24c309543d2c6 |
15 | 105cb5db846e0 |
hex | 7912710dc9fe |
133120113101310 has 64 divisors (see below), whose sum is σ = 328185236798784. Its totient is φ = 34532730777600.
The previous prime is 133120113101309. The next prime is 133120113101359. The reversal of 133120113101310 is 13101311021331.
It is a super-2 number, since 2×1331201131013102 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5492761 + ... + 17216580.
It is an arithmetic number, because the mean of its divisors is an integer number (5127894324981).
Almost surely, 2133120113101310 is an apocalyptic number.
133120113101310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
133120113101310 is an abundant number, since it is smaller than the sum of its proper divisors (195065123697474).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133120113101310 is a wasteful number, since it uses less digits than its factorization.
133120113101310 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 22714669.
The product of its (nonzero) digits is 162, while the sum is 21.
Adding to 133120113101310 its reverse (13101311021331), we get a palindrome (146221424122641).
The spelling of 133120113101310 in words is "one hundred thirty-three trillion, one hundred twenty billion, one hundred thirteen million, one hundred one thousand, three hundred ten".
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