Base | Representation |
---|---|
bin | 1100000110110111011110… |
… | …1101101010100110010101 |
3 | 1202010121212222111111100021 |
4 | 3001231313231222212111 |
5 | 3221101201200004343 |
6 | 44151255550145141 |
7 | 2542524355641025 |
oct | 301556755524625 |
9 | 52117788444307 |
10 | 13312112109973 |
11 | 42726a9270536 |
12 | 15abb874b21b1 |
13 | 757432c423b1 |
14 | 340449a09a85 |
15 | 18142a35e0ed |
hex | c1b77b6a995 |
13312112109973 has 2 divisors, whose sum is σ = 13312112109974. Its totient is φ = 13312112109972.
The previous prime is 13312112109917. The next prime is 13312112110039. The reversal of 13312112109973 is 37990121121331.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6800949426769 + 6511162683204 = 2607863^2 + 2551698^2 .
It is a cyclic number.
It is not a de Polignac number, because 13312112109973 - 233 = 13303522175381 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312112109173) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656056054986 + 6656056054987.
It is an arithmetic number, because the mean of its divisors is an integer number (6656056054987).
Almost surely, 213312112109973 is an apocalyptic number.
It is an amenable number.
13312112109973 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312112109973 is an equidigital number, since it uses as much as digits as its factorization.
13312112109973 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 61236, while the sum is 43.
The spelling of 13312112109973 in words is "thirteen trillion, three hundred twelve billion, one hundred twelve million, one hundred nine thousand, nine hundred seventy-three".
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