13312112110039 has 2 divisors, whose sum is σ = 13312112110040. Its totient is φ = 13312112110038.

The previous prime is 13312112109973. The next prime is 13312112110049. The reversal of 13312112110039 is 93001121121331.

It is a strong prime.

It is an emirp because it is prime and its reverse (93001121121331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13312112110039 - 2¹⁷ = 13312111978967 is a prime.

It is a super-3 number, since 3×13312112110039³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13312112109989 and 13312112110016.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13312112110049) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656056055019 + 6656056055020.

It is an arithmetic number, because the mean of its divisors is an integer number (6656056055020).

Almost surely, 2^{13312112110039} is an apocalyptic number.

13312112110039 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312112110039 is an equidigital number, since it uses as much as digits as its factorization.

13312112110039 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972, while the sum is 28.

The spelling of 13312112110039 in words is "thirteen trillion, three hundred twelve billion, one hundred twelve million, one hundred ten thousand, thirty-nine".