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133122014 = 266561007
BaseRepresentation
bin1111110111101…
…00011111011110
3100021111022001222
413323310133132
5233034401024
621113133342
73204342554
oct773643736
9307438058
10133122014
11691645a3
12386ba252
132176c82c
1413973bd4
15ba4885e
hex7ef47de

133122014 has 4 divisors (see below), whose sum is σ = 199683024. Its totient is φ = 66561006.

The previous prime is 133122007. The next prime is 133122049. The reversal of 133122014 is 410221331.

133122014 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×1331220142 = 35442941222832392, which contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 133121983 and 133122001.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 33280502 + ... + 33280505.

It is an arithmetic number, because the mean of its divisors is an integer number (49920756).

Almost surely, 2133122014 is an apocalyptic number.

133122014 is a deficient number, since it is larger than the sum of its proper divisors (66561010).

133122014 is an equidigital number, since it uses as much as digits as its factorization.

133122014 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 66561009.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 133122014 is about 11537.8513597637. The cubic root of 133122014 is about 510.6029188885.

Adding to 133122014 its reverse (410221331), we get a palindrome (543343345).

The spelling of 133122014 in words is "one hundred thirty-three million, one hundred twenty-two thousand, fourteen".

Divisors: 1 2 66561007 133122014