Base | Representation |
---|---|
bin | 11000110010111100… |
… | …00011010001101111 |
3 | 1021100202021100002222 |
4 | 30121132003101233 |
5 | 204230411210111 |
6 | 10040542505555 |
7 | 650613626651 |
oct | 143136032157 |
9 | 37322240088 |
10 | 13312210031 |
11 | 571143947a |
12 | 26b62952bb |
13 | 1341c86273 |
14 | 903dda6d1 |
15 | 52da737db |
hex | 31978346f |
13312210031 has 2 divisors, whose sum is σ = 13312210032. Its totient is φ = 13312210030.
The previous prime is 13312209991. The next prime is 13312210039. The reversal of 13312210031 is 13001221331.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13312210031 - 214 = 13312193647 is a prime.
It is a super-2 number, since 2×133122100312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13312209991 and 13312210009.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13312210039) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656105015 + 6656105016.
It is an arithmetic number, because the mean of its divisors is an integer number (6656105016).
Almost surely, 213312210031 is an apocalyptic number.
13312210031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13312210031 is an equidigital number, since it uses as much as digits as its factorization.
13312210031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 13312210031 its reverse (13001221331), we get a palindrome (26313431362).
The spelling of 13312210031 in words is "thirteen billion, three hundred twelve million, two hundred ten thousand, thirty-one".
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