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133122123000 = 2334538319801
BaseRepresentation
bin111101111111010110…
…0100110010011111000
3110201121111202112020000
41323332230212103320
54140113230414000
6141053325033000
712421614242526
oct1737654462370
9421544675200
10133122123000
1151502a71379
12219723b5760
13c7269773a9
14662bdc1316
1536e1ecc000
hex1efeb264f8

133122123000 has 320 divisors, whose sum is σ = 470966015520. Its totient is φ = 35069760000.

The previous prime is 133122122977. The next prime is 133122123007. The reversal of 133122123000 is 321221331.

133122123000 is a `hidden beast` number, since 1 + 331 + 22 + 12 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (133122123007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 6713100 + ... + 6732900.

Almost surely, 2133122123000 is an apocalyptic number.

133122123000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 133122123000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (235483007760).

133122123000 is an abundant number, since it is smaller than the sum of its proper divisors (337843892520).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

133122123000 is a wasteful number, since it uses less digits than its factorization.

133122123000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19917 (or 19894 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 133122123000 its reverse (321221331), we get a palindrome (133443344331).

It can be divided in two parts, 13312 and 2123000, that added together give a palindrome (2136312).

The spelling of 133122123000 in words is "one hundred thirty-three billion, one hundred twenty-two million, one hundred twenty-three thousand".