Base | Representation |
---|---|
bin | 10011010111110010111… |
… | …110010010111011111110 |
3 | 11201021010002202101122112 |
4 | 103113302332102323332 |
5 | 133302320123424410 |
6 | 2455315444414022 |
7 | 165114622305356 |
oct | 23276276227376 |
9 | 4637102671575 |
10 | 1331221311230 |
11 | 4736277a8448 |
12 | 195bbb3a7312 |
13 | 986c2505bb5 |
14 | 48607cadb66 |
15 | 24964d99105 |
hex | 135f2f92efe |
1331221311230 has 32 divisors (see below), whose sum is σ = 2399371447968. Its totient is φ = 531783856000.
The previous prime is 1331221311187. The next prime is 1331221311359. The reversal of 1331221311230 is 321131221331.
It is a super-2 number, since 2×13312213112302 (a number of 25 digits) contains 22 as substring.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 1331221311196 and 1331221311205.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 24362540 + ... + 24417120.
It is an arithmetic number, because the mean of its divisors is an integer number (74980357749).
Almost surely, 21331221311230 is an apocalyptic number.
1331221311230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1331221311230 is a deficient number, since it is larger than the sum of its proper divisors (1068150136738).
1331221311230 is a wasteful number, since it uses less digits than its factorization.
1331221311230 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57772.
The product of its (nonzero) digits is 648, while the sum is 23.
Adding to 1331221311230 its reverse (321131221331), we get a palindrome (1652352532561).
The spelling of 1331221311230 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-one million, three hundred eleven thousand, two hundred thirty".
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