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1331222200133 = 7190174600019
BaseRepresentation
bin10011010111110011000…
…001101011111101000101
311201021010011102112222212
4103113303001223331011
5133302320340401013
62455315515433205
7165114633000050
oct23276301537505
94637104375885
101331222200133
11473628255281
12195bbb755805
13986c2757687
1448608061a97
1524964ec26a8
hex135f306bf45

1331222200133 has 4 divisors (see below), whose sum is σ = 1521396800160. Its totient is φ = 1141047600108.

The previous prime is 1331222200057. The next prime is 1331222200157. The reversal of 1331222200133 is 3310022221331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331222200133 - 214 = 1331222183749 is a prime.

It is a super-2 number, since 2×13312222001332 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331222200099 and 1331222200108.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331222200333) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 95087300003 + ... + 95087300016.

It is an arithmetic number, because the mean of its divisors is an integer number (380349200040).

Almost surely, 21331222200133 is an apocalyptic number.

It is an amenable number.

1331222200133 is a deficient number, since it is larger than the sum of its proper divisors (190174600027).

1331222200133 is an equidigital number, since it uses as much as digits as its factorization.

1331222200133 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 190174600026.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 1331222200133 its reverse (3310022221331), we get a palindrome (4641244421464).

The spelling of 1331222200133 in words is "one trillion, three hundred thirty-one billion, two hundred twenty-two million, two hundred thousand, one hundred thirty-three".

Divisors: 1 7 190174600019 1331222200133