133122301101131 has 4 divisors (see below), whose sum is σ = 133134944506200. Its totient is φ = 133109657696064.

The previous prime is 133122301101109. The next prime is 133122301101149. The reversal of 133122301101131 is 131101103221331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-133122301101131 is a prime.

It is a super-2 number, since 2×133122301101131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 133122301101097 and 133122301101106.

It is not an unprimeable number, because it can be changed into a prime (133122301101331) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6321686741 + ... + 6321707798.

It is an arithmetic number, because the mean of its divisors is an integer number (33283736126550).

Almost surely, 2^{133122301101131} is an apocalyptic number.

133122301101131 is a deficient number, since it is larger than the sum of its proper divisors (12643405069).

133122301101131 is a wasteful number, since it uses less digits than its factorization.

133122301101131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12643405068.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 133122301101131 its reverse (131101103221331), we get a palindrome (264223404322462).

The spelling of 133122301101131 in words is "one hundred thirty-three trillion, one hundred twenty-two billion, three hundred one million, one hundred one thousand, one hundred thirty-one".