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13312233000000 = 26325611472861
BaseRepresentation
bin1100000110110111111011…
…1010110100110001000000
31202010122012101222100021200
43001231332322310301000
53221101423122000000
644151315545221200
72542530354330054
oct301557672646100
952118171870250
1013312233000000
11427276052aa50
1215abbbba91800
13757451cbb45c
1434045bab7c64
15181435c8d500
hexc1b7eeb4c40

13312233000000 has 1176 divisors, whose sum is σ = 53157392076672. Its totient is φ = 3157440000000.

The previous prime is 13312232999869. The next prime is 13312233000019. The reversal of 13312233000000 is 33221331.

13312233000000 is a `hidden beast` number, since 1 + 331 + 2 + 2 + 330 + 0 + 0 + 0 + 0 + 0 = 666.

13312233000000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is an unprimeable number.

It is a polite number, since it can be written in 167 ways as a sum of consecutive naturals, for example, 4652998570 + ... + 4653001430.

Almost surely, 213312233000000 is an apocalyptic number.

13312233000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312233000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26578696038336).

13312233000000 is an abundant number, since it is smaller than the sum of its proper divisors (39845159076672).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312233000000 is an equidigital number, since it uses as much as digits as its factorization.

13312233000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2967 (or 2929 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 18.

Adding to 13312233000000 its reverse (33221331), we get a palindrome (13312266221331).

The spelling of 13312233000000 in words is "thirteen trillion, three hundred twelve billion, two hundred thirty-three million", and thus it is an aban number.