13312241300051 has 2 divisors, whose sum is σ = 13312241300052. Its totient is φ = 13312241300050.

The previous prime is 13312241299997. The next prime is 13312241300053. The reversal of 13312241300051 is 15000314221331.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13312241300051 - 2¹⁴ = 13312241283667 is a prime.

It is a super-2 number, since 2×13312241300051² (a number of 27 digits) contains 22 as substring.

Together with 13312241300053, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13312241300053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656120650025 + 6656120650026.

It is an arithmetic number, because the mean of its divisors is an integer number (6656120650026).

Almost surely, 2^{13312241300051} is an apocalyptic number.

13312241300051 is a deficient number, since it is larger than the sum of its proper divisors (1).

13312241300051 is an equidigital number, since it uses as much as digits as its factorization.

13312241300051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 13312241300051 its reverse (15000314221331), we get a palindrome (28312555521382).

The spelling of 13312241300051 in words is "thirteen trillion, three hundred twelve billion, two hundred forty-one million, three hundred thousand, fifty-one".