13312241344040 has 32 divisors (see below), whose sum is σ = 29955650035680. Its totient is φ = 5324344180032.

The previous prime is 13312241344027. The next prime is 13312241344049. The reversal of 13312241344040 is 4044314221331.

It is a junction number, because it is equal to n+sod(n) for n = 13312241343988 and 13312241344006.

It is not an unprimeable number, because it can be changed into a prime (13312241344049) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 16870634 + ... + 17642073.

It is an arithmetic number, because the mean of its divisors is an integer number (936114063615).

Almost surely, 2^{13312241344040} is an apocalyptic number.

13312241344040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13312241344040 is an abundant number, since it is smaller than the sum of its proper divisors (16643408691640).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312241344040 is a wasteful number, since it uses less digits than its factorization.

13312241344040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 34522361 (or 34522357 counting only the distinct ones).

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 13312241344040 its reverse (4044314221331), we get a palindrome (17356555565371).

The spelling of 13312241344040 in words is "thirteen trillion, three hundred twelve billion, two hundred forty-one million, three hundred forty-four thousand, forty".