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13312244000000 = 285611302551
BaseRepresentation
bin1100000110110111111110…
…0100110010010100000000
31202010122020011200012110002
43001231333210302110000
53221101433431000000
644151321021055132
72542530546663041
oct301557744622400
952118204605402
1013312244000000
114272766763460
1215b00036b74a8
1375745437022a
1434045d33c8c8
15181436c128d5
hexc1b7f932500

13312244000000 has 252 divisors, whose sum is σ = 36234865562784. Its totient is φ = 4840800000000.

The previous prime is 13312243999961. The next prime is 13312244000053. The reversal of 13312244000000 is 44221331.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 27 ways as a sum of consecutive naturals, for example, 43848725 + ... + 44151275.

Almost surely, 213312244000000 is an apocalyptic number.

13312244000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13312244000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18117432781392).

13312244000000 is an abundant number, since it is smaller than the sum of its proper divisors (22922621562784).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13312244000000 is an frugal number, since it uses more digits than its factorization.

13312244000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 302608 (or 302569 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 20.

Adding to 13312244000000 its reverse (44221331), we get a palindrome (13312288221331).

The spelling of 13312244000000 in words is "thirteen trillion, three hundred twelve billion, two hundred forty-four million", and thus it is an aban number.