Base | Representation |
---|---|
bin | 111101111111010110… |
… | …1110100001100010111 |
3 | 110201121112100201211002 |
4 | 1323332231310030113 |
5 | 4140113321121012 |
6 | 141053335533515 |
7 | 12421620041552 |
oct | 1737655641427 |
9 | 421545321732 |
10 | 133122442007 |
11 | 5150316a015 |
12 | 2197252a29b |
13 | c726a59659 |
14 | 662c065699 |
15 | 36e20417c2 |
hex | 1efeb74317 |
133122442007 has 2 divisors, whose sum is σ = 133122442008. Its totient is φ = 133122442006.
The previous prime is 133122441961. The next prime is 133122442021. The reversal of 133122442007 is 700244221331.
It is a strong prime.
It is an emirp because it is prime and its reverse (700244221331) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 133122442007 - 212 = 133122437911 is a prime.
It is a super-3 number, since 3×1331224420073 (a number of 34 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133122442087) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561221003 + 66561221004.
It is an arithmetic number, because the mean of its divisors is an integer number (66561221004).
Almost surely, 2133122442007 is an apocalyptic number.
133122442007 is a deficient number, since it is larger than the sum of its proper divisors (1).
133122442007 is an equidigital number, since it uses as much as digits as its factorization.
133122442007 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 29.
Adding to 133122442007 its reverse (700244221331), we get a palindrome (833366663338).
The spelling of 133122442007 in words is "one hundred thirty-three billion, one hundred twenty-two million, four hundred forty-two thousand, seven".
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