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133122442007 is a prime number
BaseRepresentation
bin111101111111010110…
…1110100001100010111
3110201121112100201211002
41323332231310030113
54140113321121012
6141053335533515
712421620041552
oct1737655641427
9421545321732
10133122442007
115150316a015
122197252a29b
13c726a59659
14662c065699
1536e20417c2
hex1efeb74317

133122442007 has 2 divisors, whose sum is σ = 133122442008. Its totient is φ = 133122442006.

The previous prime is 133122441961. The next prime is 133122442021. The reversal of 133122442007 is 700244221331.

It is a strong prime.

It is an emirp because it is prime and its reverse (700244221331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 133122442007 - 212 = 133122437911 is a prime.

It is a super-3 number, since 3×1331224420073 (a number of 34 digits) contains 333 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (133122442087) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561221003 + 66561221004.

It is an arithmetic number, because the mean of its divisors is an integer number (66561221004).

Almost surely, 2133122442007 is an apocalyptic number.

133122442007 is a deficient number, since it is larger than the sum of its proper divisors (1).

133122442007 is an equidigital number, since it uses as much as digits as its factorization.

133122442007 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 29.

Adding to 133122442007 its reverse (700244221331), we get a palindrome (833366663338).

The spelling of 133122442007 in words is "one hundred thirty-three billion, one hundred twenty-two million, four hundred forty-two thousand, seven".