Base | Representation |
---|---|
bin | 111101111111010110… |
… | …1110100001100100101 |
3 | 110201121112100201211121 |
4 | 1323332231310030211 |
5 | 4140113321121041 |
6 | 141053335533541 |
7 | 12421620041602 |
oct | 1737655641445 |
9 | 421545321747 |
10 | 133122442021 |
11 | 5150316a028 |
12 | 2197252a2b1 |
13 | c726a5966a |
14 | 662c0656a9 |
15 | 36e20417d1 |
hex | 1efeb74325 |
133122442021 has 2 divisors, whose sum is σ = 133122442022. Its totient is φ = 133122442020.
The previous prime is 133122442007. The next prime is 133122442031. The reversal of 133122442021 is 120244221331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 85723056225 + 47399385796 = 292785^2 + 217714^2 .
It is a cyclic number.
It is not a de Polignac number, because 133122442021 - 235 = 98762703653 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (133122442031) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 66561221010 + 66561221011.
It is an arithmetic number, because the mean of its divisors is an integer number (66561221011).
Almost surely, 2133122442021 is an apocalyptic number.
It is an amenable number.
133122442021 is a deficient number, since it is larger than the sum of its proper divisors (1).
133122442021 is an equidigital number, since it uses as much as digits as its factorization.
133122442021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 133122442021 its reverse (120244221331), we get a palindrome (253366663352).
The spelling of 133122442021 in words is "one hundred thirty-three billion, one hundred twenty-two million, four hundred forty-two thousand, twenty-one".
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