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1331252120053 = 8110671641359
BaseRepresentation
bin10011010111110100110…
…011110100100111110101
311201021012020201122102001
4103113310303310213311
5133302401020320203
62455322505015301
7165115445213122
oct23276463644765
94637166648361
101331252120053
11473643130589
12196009784531
13986c8a0207b
144860c00d749
152496793291d
hex135f4cf49f5

1331252120053 has 4 divisors (see below), whose sum is σ = 1331254572480. Its totient is φ = 1331249667628.

The previous prime is 1331252120041. The next prime is 1331252120089. The reversal of 1331252120053 is 3500212521331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1331252120053 - 217 = 1331251988981 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331252120153) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9613 + ... + 1631746.

It is an arithmetic number, because the mean of its divisors is an integer number (332813643120).

Almost surely, 21331252120053 is an apocalyptic number.

It is an amenable number.

1331252120053 is a deficient number, since it is larger than the sum of its proper divisors (2452427).

1331252120053 is an equidigital number, since it uses as much as digits as its factorization.

1331252120053 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2452426.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 1331252120053 its reverse (3500212521331), we get a palindrome (4831464641384).

The spelling of 1331252120053 in words is "one trillion, three hundred thirty-one billion, two hundred fifty-two million, one hundred twenty thousand, fifty-three".

Divisors: 1 811067 1641359 1331252120053