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1331301120000 = 2113541971257
BaseRepresentation
bin10011010111110111101…
…110101111100000000000
311201021022122221002200220
4103113313232233200000
5133303001041320000
62455331415143040
7165116611544115
oct23276756574000
94637278832626
101331301120000
11473668858a05
12196022074a80
1398705bca217
144861472690c
152496bdb11a0
hex135f7baf800

1331301120000 has 960 divisors, whose sum is σ = 4752773625600. Its totient is φ = 330301440000.

The previous prime is 1331301119983. The next prime is 1331301120001. The reversal of 1331301120000 is 211031331.

It is a tau number, because it is divible by the number of its divisors (960).

It is a super-2 number, since 2×13313011200002 (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1331301120001) by changing a digit.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 5180159872 + ... + 5180160128.

It is an arithmetic number, because the mean of its divisors is an integer number (4950805860).

Almost surely, 21331301120000 is an apocalyptic number.

1331301120000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1331301120000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2376386812800).

1331301120000 is an abundant number, since it is smaller than the sum of its proper divisors (3421472505600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1331301120000 is an equidigital number, since it uses as much as digits as its factorization.

1331301120000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 392 (or 357 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 1331301120000 its reverse (211031331), we get a palindrome (1331512151331).

The spelling of 1331301120000 in words is "one trillion, three hundred thirty-one billion, three hundred one million, one hundred twenty thousand".