Base | Representation |
---|---|
bin | 10011010111111000100… |
… | …001011110111000000001 |
3 | 11201021100120221212120202 |
4 | 103113320201132320001 |
5 | 133303012442434444 |
6 | 2455333012214545 |
7 | 165120132603221 |
oct | 23277041367001 |
9 | 4637316855522 |
10 | 1331314421249 |
11 | 47367531337a |
12 | 19602660a455 |
13 | 987088a6597 |
14 | 486163ca081 |
15 | 2496d13c34e |
hex | 135f885ee01 |
1331314421249 has 2 divisors, whose sum is σ = 1331314421250. Its totient is φ = 1331314421248.
The previous prime is 1331314421141. The next prime is 1331314421251. The reversal of 1331314421249 is 9421244131331.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1318225459600 + 13088961649 = 1148140^2 + 114407^2 .
It is a cyclic number.
It is not a de Polignac number, because 1331314421249 - 28 = 1331314420993 is a prime.
Together with 1331314421251, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1331314427249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665657210624 + 665657210625.
It is an arithmetic number, because the mean of its divisors is an integer number (665657210625).
Almost surely, 21331314421249 is an apocalyptic number.
It is an amenable number.
1331314421249 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331314421249 is an equidigital number, since it uses as much as digits as its factorization.
1331314421249 is an evil number, because the sum of its binary digits is even.
The product of its digits is 62208, while the sum is 38.
The spelling of 1331314421249 in words is "one trillion, three hundred thirty-one billion, three hundred fourteen million, four hundred twenty-one thousand, two hundred forty-nine".
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