Base | Representation |
---|---|
bin | 10011010111111000100… |
… | …001011110111000000011 |
3 | 11201021100120221212120211 |
4 | 103113320201132320003 |
5 | 133303012442440001 |
6 | 2455333012214551 |
7 | 165120132603223 |
oct | 23277041367003 |
9 | 4637316855524 |
10 | 1331314421251 |
11 | 473675313381 |
12 | 19602660a457 |
13 | 987088a6599 |
14 | 486163ca083 |
15 | 2496d13c351 |
hex | 135f885ee03 |
1331314421251 has 2 divisors, whose sum is σ = 1331314421252. Its totient is φ = 1331314421250.
The previous prime is 1331314421249. The next prime is 1331314421287. The reversal of 1331314421251 is 1521244131331.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1331314421251 - 21 = 1331314421249 is a prime.
Together with 1331314421249, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1331314421351) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 665657210625 + 665657210626.
It is an arithmetic number, because the mean of its divisors is an integer number (665657210626).
Almost surely, 21331314421251 is an apocalyptic number.
1331314421251 is a deficient number, since it is larger than the sum of its proper divisors (1).
1331314421251 is an equidigital number, since it uses as much as digits as its factorization.
1331314421251 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 8640, while the sum is 31.
Adding to 1331314421251 its reverse (1521244131331), we get a palindrome (2852558552582).
The spelling of 1331314421251 in words is "one trillion, three hundred thirty-one billion, three hundred fourteen million, four hundred twenty-one thousand, two hundred fifty-one".
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