Base | Representation |
---|---|
bin | 11110010001010100111000… |
… | …001101000110000101011100 |
3 | 122110101022002001210111121011 |
4 | 132101110320031012011130 |
5 | 114422213411310343004 |
6 | 1151052003343345004 |
7 | 40020321110334220 |
oct | 3621247015060534 |
9 | 573338061714534 |
10 | 133132044231004 |
11 | 39468a8a250045 |
12 | 12b21a702b2164 |
13 | 59393b464c550 |
14 | 24c38a7c50780 |
15 | 105d10b34e004 |
hex | 79153834615c |
133132044231004 has 24 divisors (see below), whose sum is σ = 286745941421408. Its totient is φ = 52667621893440.
The previous prime is 133132044230963. The next prime is 133132044231059. The reversal of 133132044231004 is 400132440231331.
It is a super-2 number, since 2×1331320442310042 (a number of 29 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 182873686767 + ... + 182873687494.
Almost surely, 2133132044231004 is an apocalyptic number.
133132044231004 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
133132044231004 is an abundant number, since it is smaller than the sum of its proper divisors (153613897190404).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
133132044231004 is a wasteful number, since it uses less digits than its factorization.
133132044231004 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 365747374285 (or 365747374283 counting only the distinct ones).
The product of its (nonzero) digits is 20736, while the sum is 31.
Adding to 133132044231004 its reverse (400132440231331), we get a palindrome (533264484462335).
The spelling of 133132044231004 in words is "one hundred thirty-three trillion, one hundred thirty-two billion, forty-four million, two hundred thirty-one thousand, four".
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