13313400047 has 2 divisors, whose sum is σ = 13313400048. Its totient is φ = 13313400046.

The previous prime is 13313400007. The next prime is 13313400049. The reversal of 13313400047 is 74000431331.

It is a strong prime.

It is an emirp because it is prime and its reverse (74000431331) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13313400047 - 2¹⁴ = 13313383663 is a prime.

It is a super-2 number, since 2×13313400047² (a number of 21 digits) contains 22 as substring.

Together with 13313400049, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13313399989 and 13313400025.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13313400049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6656700023 + 6656700024.

It is an arithmetic number, because the mean of its divisors is an integer number (6656700024).

Almost surely, 2^13313400047 is an apocalyptic number.

13313400047 is a deficient number, since it is larger than the sum of its proper divisors (1).

13313400047 is an equidigital number, since it uses as much as digits as its factorization.

13313400047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3024, while the sum is 26.

Adding to 13313400047 its reverse (74000431331), we get a palindrome (87313831378).

The spelling of 13313400047 in words is "thirteen billion, three hundred thirteen million, four hundred thousand, forty-seven".